Divide a line segment of length 9 cm internally in the ratio 4: 3. Also, give the justification.

### Asked by Topperlearning User | 27th Jul, 2017, 01:45: PM

###

Steps of construction.

Steps of construction.

i. Draw a line segment PQ = 9cm.

ii. Draw any ray making an acute angle QPX with PQ.

iii. Along PX, mark off 7 (4+3) points P_{1, }P_{2,} P_{3,} P_{4,} P_{5,} P_{6,} P_{7} such that PP_{1} = P_{1}P_{2}

_{2}P

_{3}=P

_{3}P

_{4}= P

_{4}P

_{5}= P

_{5}P

_{6}= P

_{6}P

_{7}

iv. Join QP_{7}.

v. Through P_{4} draw a line P_{4}A parallel to P_{7}Q by making an angle equal to PP_{7}Q intersecting PQ at A.

vi. The point A so obtained is the required point, which divides PQ internally in the ratio 4: 3

Justification: _{}

### Answered by | 27th Jul, 2017, 03:45: PM

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